 In this video, we provide the solution to question number one, for the practice final exam for math 1210, in which case we're asked to compute the limit as x approaches two of the square root of 2x squared plus one over 3x minus two. My initial thoughts are, let's hope continuity works. Let's just plug in x equals two and see what happens. If we get zero over zero or something, we can adjust, but let's see what happens when we just plug in two. So we put that into the formula. I can see that the denominator is not going to go to zero. We're going to get six minus two, which ultimately becomes a four, which is pretty good. In the numerator, we get two squared, which is four times another two is eight. So we get eight plus one, which is nine. So we're going to take the square root of nine four, which nine and four are both perfect squares. We end up with three halves. So we see the correct answer is E, just simply by using continuity and plugging in x equals two.