 Hello and welcome to the session. In this session we discussed the following question that says A's income is 20% less than that of B. How much percent is B's income more than that of A? Let's first recall the formula for increased percent. This is equal to increase upon original value into 100% and decrease percent is equal to decrease upon original value into 100%. This is the key idea to be used in this question. Let's move on to the solution now. First we assume let B's income be equal to rupees 100. Now as any question is given that A's income is 20% less than that of B. So then we have A's income would be equal to rupees 100 minus rupees 20 and this is equal to rupees 80 since A's income is 20% less than that of B. Now if A's income is rupees 80 then B's income is equal to rupees 100. So if we have A's income is rupees 100 then B's income would be equal to rupees 100 upon 80 into 100. Now this 0 cancels with this 0. Now 4, 2 times is 8 and 4 25 times is 100 and 2 5 times is 10. So this is equal to rupees 25 into 5 equal to rupees 125 would be B's income when given that A's income is rupees 100. So obviously B's income is more than that of A's income so hence we have B's income is more than that of A by 25% since rupees 125 minus rupees 100 is 25 so that would be 25%. So 25% is our final answer. This completes the session. Hope you understood the solution for this question.