 The velocity is in that direction where the 4.9 point place does not take legs to that point but meanwhile it will just dip because of gravity. So you can find the angle with the horizontal using that information. Initial angle of projection you can find out. You can find theta. We are working once again to find the x coordinate. So I have to find what is this? That is the question. Are you understood the question? That is only earlier as well. What is given to me? This will give me 1. So s is minus y which is uy. It will be 1 minus half p is 1. So uy will be 1. uy is 4. This is equal to u sin theta. Yes or no? It tangent to sin theta is root 5 by 2. So 2 root 5. Later for a second. So this is u. This is 2 cos theta. 2 root 5 cos theta is the velocity of x axis. So ux is 2 root 5 into cos theta is what? 1 by 2. Is your distance along x axis? So answer is 2. That's right. Cos theta doesn't change. So initial question whatever it is. u cos the u sin theta is the velocity of sin 45. Take comfort of this one. 1, 2, 3. So using this you can find out what is u and v in terms of h. And then what is given is now that the angle is 60 degree. What is that angle it makes when it strikes the ground. Right? So you just play around with these equations you can answer. Can you write it now? Just write down the equations. Don't try to solve it right now. Write down the equation. Then when you look at the equation you will see how it can be done like that. In first scenario and in second scenario, the specimen around y axis is same. Don't bring in time in the equation. P should not come in the equation. v square is equal to u square plus 2 a s along y axis. So this is v y square should be equal to u y square minus of you have to find a realistic diagram. For the second case v y dash square is equal to u sin 16 plus 2 g h. Substitute that. This is your substitute here. So you can rearrange and then you can get the value of v y. You got it? Okay, only one person is correct. See I cannot spoon feed you each and every step. Do it yourself. I have written all the equations that are required to solve. There are millions of questions. I cannot spoon feed you all the millions type of questions. You need to understand how to solve the question. Alright, same speed and different angles. They have sin theta 1 sin theta 2 cos theta 2. When this will happen? 90 degree. Okay, but anyways, even if you don't, theta 1 by g, p2 is equal to u sin theta 2 by g. When sin theta 1 cos theta 2 is equal to sin theta 2 cos theta 2. When sin theta 1 becomes cos theta 2 and cos theta 1 becomes sin theta 2. Okay, questions and these questions. So you got velocity v cos theta 3. Oh, should be same? Why? Because there is no acceleration on x axis. That is the basic of constant throughout the projectile. That is what I am using here. Finally, velocity v is component. So I will use the initial angle.