 Hi and welcome to the session. I am Asha and I am going to help you with the following question which says, find the domain and range of the real valued function f defined by f x is equal to root over x minus 1. So let us begin with the solution and here we are given a function f at x defined by root over x minus 1 and here f is a real function and we need to find the domain range of f. Now let the function fx is equal to y. So this implies y is equal to root over x minus 1 then the set of values which x can take is called the domain of f. The set of values which y can take is called the range of f and since the given function fx is a real function therefore root over x minus 1 is defined x minus 1 is greater than or equal to 0 or x it is greater than or equal to 1 for all x belonging to the real functions out. Therefore domain of the function f will be closed interval 1 to infinity and again since root over x minus 1 is the positive square root of minus 1 and x is greater than or equal to 1 this implies that the function y is greater than or equal to 0 and hence the range of the function is equal to 0 with closed interval up to infinity and thus the answers are domain from closed interval 1 to infinity and range of the function is from the closed interval 0 to infinity. So this completes the solution hope you enjoyed it take care and have a good day.