 Hello and welcome to the session. In this session, we are going to discuss geometrical interpretation of cross product of two vectors. Let O A be equal to vector A and O B be equal to vector B as two non-paraments and non-null vectors. O A is equal to vector A and O B is equal to vector B are the two non-paraments and non-null vectors. Let theta be the angle between O A and O B. A is equal to modulus of vector A and B is equal to modulus of vector B. Theta is the angle between O A and O B and M is the unit vector by definition vector A cross vector B is equal to A B sine of theta dot m cap or we can also write modulus of vector A cross vector B is equal to modulus of A B sine of theta dot m cap which can also be written as A B sine of theta into modulus of m cap and we know that modulus of the unit vector m is 1 so we have A B sine of theta and we know that A is equal to modulus of vector A and B is equal to modulus of vector B so modulus of vector A into modulus of vector B into sine of theta into half modulus of vector A cross vector B is equal to modulus of vector A into modulus of vector B into sine of theta Mark this equation as 1, now complete the parallelogram O A C B, then the area of the parallelogram O A C B is equal to twice of area of triangle O A B, area of triangle O A B is given by 1 by 2 into O A into O B into sin of theta, so we have twice of 1 by 2 into O A into O B into sin of angle theta which is equal to O A is the modulus of vector A, O B is the modulus of vector B into sin of angle theta and from the equation 1 we know that modulus of vector A cross vector B is equal to modulus of vector A into modulus of vector B into sin of angle theta, so we can write it as modulus of vector A cross vector B therefore vector A cross vector B is a vector perpendicular to both vector A and vector B whose magnitude is equal to the area of the parallelogram whose adjacent sides are the vectors A and B, vector area of triangle O A B is equal to 1 by 2 into area of parallelogram O A C B which is equal to 1 by 2 into vector A cross vector B therefore area of triangle O A B is equal to 1 by 2 into modulus of vector A cross vector B, this completes our session hope you enjoyed this session.