 Hi and welcome to the session. I am Deepika here. Let's discuss the question in given figure find 10p minus quarter now we know that according to Pythagoras theorem triangle ABC right angle at B hypotenuse scale is equal to the sum of the scales of other two sides that is AC square is equal to AB square plus BC square and 10 theta is equal to side opposite to angle theta side adjacent to angle theta or theta is equal to side adjacent to angle theta upon side opposite to angle theta So this is a key idea behind our question. Take the help of this key idea to solve the above question So let's start the solution angle PQR, PQ is 12 centimeter and PR is given to us 13 centimeter. This side QR is not given to us So we will first find out the side QR Now according to the Pythagoras theorem inch angle PQR right angle at Q We have square is equal to Q square plus QR square. Now PR square is equal to 13 square and PQ square is 12 square Plus QR square this we have to find QR square is equal to 13 square minus 12 square this implies 13 plus 12 into 13 minus 12 is equal to QR square So this is equal to 25 into 1 is equal to QR square. This implies QR is equal to 5 that is QR is our 5 centimeter Now we have PQ is equal to 12 centimeter QR is equal to 5 centimeter and PR is equal to 13 centimeter. Now We have to find 10 P minus quarter Now 10 P is equal to side opposite to angle P That is QR upon side adjacent to angle P that is PQ and This is equal to 5 over 12 and quarter is equal to side adjacent to angle R that is QR Upon side opposite to angle R that is PQ and this is also equal to 5 by 12 this implies 10 P minus quarter is equal to 5 by 12 minus 5 by 12 and This is equal to 0 Hence 10 P minus quarter is equal to 0. So the answer for the above question is 0. I Hope the question is clear to you. Bye and take care