 Hi and welcome to the session. Let's work out the following question. The question says, construct a triangle ABC in which BC is 6.5 centimeter, angle A is 60 degree and median AB is equal to 4.5 centimeter. Let's start with a solution to this question. We see the steps of construction involved in solving this question. Step one is draw a line BC of 6.5 centimeter. So let this be the line BC of 6.5 centimeter. Step two is draw the perpendicular bisector of BC. So like this we draw the perpendicular bisector of BC. Step three is at B draw an angle of 60 degree which cuts the bisector at center O. Now like this we draw an angle of 60 degree downwards to BC. Let us name this point X. So now we draw an angle of 90 degree at BX. And let the point where this meets the perpendicular bisector be called as O. Step four is make the circle at center O. So like this we make the circle at center O. Step five is taking D at center put an arc A on the circle with 4.5 centimeter from D. So like this we put an arc A on the circle with 4.5 centimeter from D. Step six is draw a line parallel to BC which meets the circle at A dash of which meets the circle at the point A dash. So like this we draw a line parallel to BC which meets the circle at the point A dash. Step seven is we get triangle ABC and triangle A dash BC as the required triangles. So triangles ABC and A dash BC are the required triangles. So this is our answer to this question. I hope that you understood the solution and enjoyed the session. Have a good day.