 Hi, and welcome to the session, I am Deepika here. Let's discuss the question. Question says, in the college situation, does the list of numbers involved make an arithmetic progression and why? The taxi fare after each kilometer, when the fare is Rs.15 for the first kilometer and Rs.8 for each additional kilometer. Let's start the solution. Before starting the solution, let us understand what do you mean, what is the meaning of arithmetic progression. An arithmetic progression is a list of numbers in which each term is obtained by adding a fixed number to the preceding term except the first term. Solution, we have the fixed fare for the first kilometer is equal to Rs.15. Now, fare for the second kilometer is equal to Rs.15 plus 8 which is equal to Rs.23. Again, fare for the third kilometer is equal to Rs.23 plus 8 which is equal to Rs.31. Thus, we have the terms as follows. First was Rs.15, second was Rs.23, Rs.31 and so on. Now, it forms an AP, case it is 8, to the preceding number. The answer for the above question is yes. The above situation forms an arithmetic progression and terms are 15, 23, 31. This forms an AP for arithmetic progression as each term, preceding term is obtained by preceding term. I hope this is clear to you. May and have a nice day.