 There's another specific problem that we can do here. How much heat must be absorbed by 125 grams of ethanol to change its temperature from 21.5 degrees Celsius to 34.8 degrees Celsius? So I've written down all of the necessary information for you to do this problem. The only thing that you need to provide for yourself is the equation for specific heat. So does anybody recall that equation? Q equals mc delta t. Yeah, very good. Q equals mc delta t. So it's asking for heat, which, of course, is q. And so the other part of the equation you need to know is that delta t. What if delta t equal? Tf. Tf. And it's tf. And it's tf. Very good. And we have both ti and tf. So we can start there. So tf is 34.8 degrees C. And ti, 21.5 degrees C, 13.3 degrees C. OK, and now it's just a plug-in drug type problem. But I like to show when we're doing these problems to expand specifically the specific heat portion so you can show the canceling of your units. So in that case, we're going to say q equals m. We've got m at 125 grams. And c, this is what I was talking about. So 2.42 joules on the top and 1 gram degrees C on the bottom. And then finally, delta t, which we figured out earlier, 13.3 degrees C. And hopefully, you can see we cancel like that. And we get joules as our final unit. And joules, of course, is a good heat unit. So we're going to multiply what we have before 13.3 times 2.42. And multiply that number by 125. So the calculator gives us 4,023.25. But if you look, all of these numbers have three significant digits. So you can only go to three digits. So even though it says 4,000, we're going to have to put that into scientific notation. So 4.02 times 10 to the third joules. Is everybody OK with that? Another way you could do this is instead of leaving it in joules, you could convert it to kilojoules. So in order to do that, it would give you a better, more manageable number. So for every 1,000 joules, that's 1 kilojoule. So cancel, cancel. So what are we going to have? 4.02 kilojoules. Any questions on that one? OK, cool.