 Hello friends welcome to the session I am Valka let us differentiate with respect to x the function in exercises 1 to 11 that is sin cube x plus cos xx. Now let us start with the solution we are given sin cube x plus cos xx so let us assume y equal to sin cube x plus cos to the power 6x. Now differentiate both sides with respect to x we get dy by dx equal to 3 sin square x into cos x plus 6 cos the power 5x into minus sin x this implies dy by dx equal to 3 sin square x into cos x minus 6 sin x cos to the power 5x this implies dy by dx equal to we take 3 sin x cos x common this gives us sin x minus cos to the power 4x so hopefully understood the solution and enjoyed the session goodbye and take care.