 Okay, so the way it works is the symbol that we have, this radical symbol that we have, the number here determines what the toll is when you go past this boundary either from this side to this side or this side to this side. For example, when there is no number here, it's basically the square root. So what it means, if I was standing over here, when we need two of me to move over here to become one, so they merge. Okay, if this was a three, then three things from here, when they cross this boundary to go this way, they become one. It also works the other way around. If you have a three up here, if you have one thing here, when you're moving this way, it has to call itself three times. So let's do an example. Let's take the cube. So we wanted the cube root of 32A to the power of five. Let's break this down into its core values, I guess that's what we're going to call it, right? If you remember, 32 is going to be, because even if you divide it by two, two times 60, and then 60, we can break down to four times. And four breaks down into two times two. We're still on the board, we're still on the board. A to the power of five just means five A's multiplied together, so you can just go. So what we're going to look for, we're going to look for triplets, because this is three here. So what we're going to do is combine three things. You can kill every branch up top, right? So this is gone, this is gone, this is gone, and these guys are gone. But those guys are gone, they're just down here. So we're going to leave our original question alone. So what we're going to do is we're going to combine triplets together, right? So we've got one, two, three, three twos here. We don't have another two to go with the two twos down there, so we're going to leave those alone because we can't combine them with triplets. Over here we've got three A's here, right? And we've got two A's left over. So these two twos come out of the symbol as a single two, and those three A's come out of that symbol as a single A. Now if there was anything up here in the front, whatever comes out of the symbol multiplies in here. So let's just add something to the front. Let's say this is five A's squared B. Let's say that's in the front. Let's make that a little thicker so it appears. So these three twos come out as a single two, and they multiply the five. That's where the answer is here. Two times five becomes ten. The three A's come out as a single A. They come out and they multiply this A. So A squared times A is going to be A cubed, because A is just basically A to the power of one, so you're adding the exponent, right? So this becomes A squared times A, which is A cubed. The B, no B's came out of the symbol, but the B came out of the radical, so the B is just straight up. And what you got left over is whatever is inside the radical. You got two A's multiplied together, which is four, and two twos multiplied together, which is four, and you got two A's multiplied together, which is A squared. And you still have the radical symbol, because you still have things left inside the radical. So this will be four A squared. I hope that makes sense. We're a little off the board, so what I'm going to do, I'm going to... Sorry, I had to move the camera. So what we're going to do is just write the answer right after the question, right? So the way it works is it becomes two times five was ten, A cubed, because we had an A squared and A came out, and you still had your B, and what you got left over is whatever is left inside the radical, right? So that's going to be the cube root of two times two is four. A times A is A squared. Okay. So your solution to this thing was just that. It just simplifies to that. So that's why prime numbers are super important, because what we're going to do is in every radical that we get, we're going to look at the symbol up here and find out what the total is to go from the inside out or to go from the outside in, because sometimes they'll ask you questions like, write it as a complete radical or one full radical, no mixed radicals or anything like this, okay? So it depends how they work the question, and that's going to depend on how you present the answer. So this is the simplest way we can go about this, and this is exactly where we're going to go about doing all the problems. And I think the best way we can do this is I'm just going to do one large problem, because when you solve one large problem, you solve multiple small problems at the same time. So if you have one big example, there's going to be all the little intricate details in there. Most of them will be in there anyway. It works generally in math or anything else you want. If you solve one big thing, then you're taking care of a whole bunch of little things, right? Life becomes easier. So what we're going to do is we're going to lay out a radical's problem and go through it and break it down. And most likely the way I'm going to do it because I have to make the problem, I'm going to start off showing you guys of how I went about making the problem, and hopefully that will clear things up for you. And then we'll go ahead and break it down again. So I guess we'll do a loop. Figure out the question. Solve the question, okay?