 Okay, so let's do another one of the spacial type projection molecules. We're going to assign R&S configuration to each stereocenter in the following molecule. Okay, so do I need to set it up again or can we just draw it? Everybody's cool with the way we do it, right? Okay, so remember, those two carbons are in the plane, so that's what we're going to draw first. This one's a little different than the last one because the lowest priorities are on opposite sides. Okay, so that's why we wanted to look at this one too. Okay, so here the hydrogen and the methyl group are in front, so let's draw those. In back of the methyl group is the hydrogen and back of the hydrogen is the bromine. And then the methyl group comes off of that carbon that has the bromine attached to it and the hydroxyl group comes off of that carbon. Okay, we have the two stereocenters that we've already identified because they each have the four different groups, okay? So one of the two stereocenters we can identify whether it's R&S already, right? Which one is it? The left or the right? The left one, right? Why is that? The hydrogen's already in the back. The hydrogen's already in the back, okay? So let's identify whether this is R&S, okay? So what's highest priority? This, this, this. Bottom, yeah, okay? So one, two, right? And so which way does this go? Twice, okay? So that's going to be S, like that. Everybody okay with that? Okay, so now what we want to do is get this hydrogen in the back, okay? So how do we do that? Well, if you think about your human projection, we can rotate and rotate again, okay? If we do that rotation two times, what's in the front will go to the top and then to the back, okay? This side of the molecule is the same and I'm going to rotate that side two times, okay? So I'm going to just redraw it over to the same, okay? So now we're going to rotate this once. Now the hydrogen is up, the bromine is down and in the back, and the alpha group is forward, okay? And on the bottom, okay? So then when we have the hydrogen in the back, a similar structure, since we've been doing things that are similar to this, so let me try to get one here, that's good, right? Once, twice, okay? So do you see? Now that's what we've got. Is everybody okay with what I did there? Okay, so if you can't do it in here, right? So we can assign stereochemistry here. The bromine's biggest, am I correct? Okay, so since it's clockwise, that's all right. So what do we have? The one that we just have. Any questions on this one? Make sense how we did that? Okay, good.