 Hello and welcome to this session. In this session we will discuss a question which says that if A is a matrix with elements in first row as minus 7, 19, 15, elements in second row as 41, minus 63, 20 and elements in third row as 2, 0 and minus 8, B is a matrix with elements in first row as 23, 18, 55, elements in second row as minus 18, minus 47, 11 and elements in third row as 39, minus 6 and minus 8 and C is a matrix with elements in first row as minus 47, 12, elements in second row as 51, 9 and 80 and elements in third row as 13, 72 and 8, then find 2A minus B plus C. Now let us start with the solution of the given question. Now here we are given matrices A, B and C and we have to find 2A minus B plus C. First of all let us find 2A. Now this is the matrix A. So 2A will be equal to 2 into the matrix A. Now here we have written the matrix A. Now to find 2A we will multiply each element of matrix A with scalar 2, multiplying each element of this matrix with 2. We have a matrix with elements in first row as 2 into minus 7, 2 into 19 and 2 into 15, then elements in second row as 2 into 41, 2 into minus 63 and 2 into 20 and elements in third row 2 into 2, 2 into 0 and 2 into minus 8. Further this is equal to a matrix with elements in first row as now 2 into minus 7 is minus 14, then 2 into 19 is 38 and 2 into 15 is 30, then elements in second row now 2 into 41 is 82, 2 into minus 63 is minus 126, 2 into 20 is 40, then elements in the third row as now 2 into 2 is 4, 2 into 0 is 0, 8 is minus 16. So here we have found minus B. Now matrix B is given to us and we have already found, now first of all let us write 2 which is equal to matrix with elements in first row as minus 14, 38 and 30, elements in second row as 82 minus 126 and 40 and elements in third row as 4, 0 and minus 6, minus B that is matrix with elements in first row as 23, 18, 55, elements in second row as minus 18, minus 47, 11 and elements in third row as 39 minus 6 of the two matrices. So this is equal to matrix with elements in first row as minus 14, minus 23, 38 minus 18 and 30 minus 55, then elements in second row as 18 will be plus 18, then minus 12 of minus 47 will be plus 47, 41, then elements in third row as 0 minus 10 matrix with elements in first minus 37, 20 minus 25 elements in second row as 129 and elements in third row as minus 35 minus B and now we have shown we are given the matrix C. Now here first of all let us write which is equal to matrix with elements in first row as minus 37, 20 and minus 25, then elements in second row as 129 and elements in third row as plus C which is equal to matrix with elements in first row as minus 47 and 12, elements in second row as 51, 9. For addition of these two matrices we add the correspond elements in first row as 37 will be minus 4, then 20, then minus 25 plus 12, 79 plus 9, 18 and elements in third row as minus 35 plus 13 and minus 8 plus 8 equal to matrix with elements in first row as 27, 13, elements in second row as 17 and 109 and elements in third row as minus 22, 78 and 0 to A minus B plus C. Now performing the given operations simultaneously to A minus B plus C is equal to here we have written the matrices A, B. Now here performing the given operations simultaneously on the corresponding elements of the three matrices we have a matrix with elements in first row into minus of minus 4 that is minus 4, then 2 into 19 minus 18 plus 15 minus into 41 minus of minus 18 will be plus 18 plus minus of minus 47 that is plus 49, then 2 into 20 minus 11 minus 39, 13, then 2 into 0 is equal to matrix minus 13 elements in second row as what we have evaluated to A minus B plus C. So the system solution of the given question and that's all for this session. Hope you all have enjoyed this session.