 Hi and welcome to the session. I am Neha and I am going to help you with the following question. The question says, prove the following identity where the angles involved are acute angles for which the expressions are defined. And the identity is 1 plus secant a upon secant a is equal to sine square a upon 1 minus cos a. Let us proceed with its solution. Here we have given the identity 1 plus secant a upon secant a is equal to sine square a upon 1 minus cos a. Now to prove this identity we will take LHS and RHS separately and we will solve them. So let us start with LHS which is equal to 1 plus secant a upon secant a. We already know that secant a is equal to 1 upon cos a. So this will be equal to 1 plus 1 upon cos a upon 1 upon cos a. Secant a is equal to 1 upon cos a. Now in numerator we will take the LCM that is cos a. So this will be equal to cos a plus 1 upon cos a into cos a upon 1 taking the reciprocal of the denominator. So here cos a and cos a will get cancelled in the numerator and denominator and we are left with 1 plus cos a upon 1 that is 1 plus cos a. So this is our LHS. Now let us move on to RHS which is equal to sine square a upon 1 minus cos a. Now we know that sine square theta plus cos square theta is equal to 1. So here sine square a will be equal to 1 minus cos square a upon 1 minus cos a as it is. Now using the identity a square minus b square is equal to a minus b into a plus b 1 minus cos square a will be equal to 1 minus cos a into 1 plus cos a upon 1 minus cos a as it is. So here 1 minus cos a will get cancelled from the numerator and denominator and we are left with 1 plus cos a upon 1 that is 1 plus cos a. So our LHS is equal to 1 plus cos a and RHS is also equal to 1 plus cos a thus LHS is equal to RHS. Hence we have proved the given identity. So with this we finished this session. Hope you must have understood the question. Goodbye, take care and have a nice day.