 Let's do this problem now, converting between Kc and Kp. So this one says a chemical engineer injects limestone into the hot, blue gas of the coal burning power plant to form lime, which scrubs sulfur dioxide from the gas and forms gypsum, calcium sulfate, dihydrate. Find Kc for the following reaction if carbon dioxide pressure is in atmosphere. So we have the formula that we were just given for the conversion of Kp to Kc, right? So it was Kp equals Kc times RT raised to the change of the numerals of gas in the reaction. So notice it's just gas in general. It doesn't matter what the identity of the actual gas is. So if you want to come over here, how do we do the change in anything? So the change in number of moles of gas is going to be the number of moles of gas final minus the number of moles of gas initial, right? And so the final number of moles of gas, just from our balanced chemical equation here, we're just going to assume it's a 1 to 1 to 1 ratio, and so I'm just going to say 1 mole. So 1 mole minus, how much gas do we have over here? Zero moles. Change is going to be 1. So we've got Kp, and we're looking for Kc, though. So we've got to rearrange this equation. Let's isolate Kc. Kc equals Kp divided by RT raised to the change in number of moles of gas. So we have Kp, 2.1 times 10 to the negative 4, divided by 0.0821 liter htm over 1 mole Kelvin. And you honestly don't even have to expand it out, because again, we're just going to kill all of our units in a second. So we've got that raised to the 1 or 1 mole or whatever you want to say. But again, all our units are going to be killed. So has everybody got it to this point? Does it make sense, at least, to get to that point? So let's just solve our problem now. So this should go to 2 safe pips. So I get 2.6 times 10 to the negative 6. No units, OK? So remember, why is this important? Because for reactions where gaseous products are formed or you have gaseous reactants, it's hard to figure out what the concentration is. So if we do it this way, we could figure out what the Kc is through using the pressure rings from our monomer. OK? Any questions on this one? Pretty straightforward, right?