 Hello and welcome to this session. In this session, we are going to discuss, in this coefficient of RAM correlation, let the RAM assigned to N in the visual range from 1 to N, then the maximum possible score, that is the number of all possible combinations of the pairs of N individuals is given by Nc2, if capital S be the total score, that is the sum of the scores of all Nc2 pairs, then in this coefficient of RAM correlation, which is denoted by tau is given by total score by maximum possible score equal to S upon Nc2 and therefore can be written as S upon N into N minus 1 by 2 as Nc2 is equal to N into N minus 1 upon 2, therefore the kindle coefficient of RAM correlation denoted by tau is equal to twice of S upon N into N minus 1. Let us take an example, the marks obtained by 8 students in English and Hindi are given below, the marks in English are given as 56, 24, 45, 44, 36, 72, 70, 23 and the marks in Hindi are given as 62, 56, 74, 66, 87, 54, 81, 35, find in this coefficient of RAM correlation. Now let us find the ranks of 8 students in English and Hindi. Now we assign ranks from 1, 2, 3 and so on from the highest to the lowest. First we assign ranks to the marks in English and we assign rank 1 to 72, rank 2 to 70, rank 3 to 56, rank 4 to 45, rank 5 to 44, rank 6 to 36, rank 7 to 24 and rank 8 to 23. Similarly we assign ranks to the marks in Hindi and we assign rank 1 to 87, rank 2 to 81, rank 3 to 74, rank 4 to 66, rank 5 to 62, rank 6 to 56, rank 7 to 54 and rank 8 to 35. Now let us find S that is the total score and we found in two ways. In the post method we rewrite the ranks assigned to the students for English and represent the corresponding marks by A, B, C, D, E, S, G and H respectively. The total score of two pairs is done. Here we have rewritten the ranks assigned to the students for English and represent the corresponding marks by A, B, C, D, E, F, G and S respectively. Now we shall write the corresponding ranks assigned to the students for Hindi. Rank assigned to D in English is greater than that of A, therefore we assign the score of plus 1 to width. Similarly, rank assigned to D in Hindi is less than that of A, therefore we assign the score of minus 1 to width. So score of A, B will be equal to plus 1 into minus 1 that is minus 1. Rank assigned to C in English is greater than that of A, therefore we assign the score of plus 1 to width and rank assigned to C in Hindi is less than that of A, therefore we assign the score of minus 1 to width. So the score of A, B will be equal to plus 1 into minus 1 that is minus 1. Rank assigned to D in English is greater than that of A, therefore we assign the score of plus 1 to width and rank assigned to D in Hindi is less than that of A, therefore we assign the score of minus 1 to width. Therefore the score of A, B will be equal to plus 1 into minus 1 that is minus 1 and similarly the scores of A, E, A, F, A, G and A, F is equal to minus 1, minus 1, minus 1 and plus 1 respectively. The total score of minus 5, similarly the score of B, C is equal to plus 1, B, G is equal to plus 1, B, E is equal to plus 1, B, F is equal to minus 1, B, G is equal to plus 1 and B, H is equal to plus 1 with the total score of plus 4. The score of C, B is equal to minus 1, that of C, E is equal to minus 1, the score of C, F is equal to minus 1, the score of C, G is equal to plus 1 and the score of C, F is equal to plus 1 with the total score of minus 1. Similarly the score of D, E is equal to plus 1, G, F is equal to minus 1, B, G is equal to plus 1, B, H is equal to plus 1 with the total score of plus 2. This core of EF is equal to minus 1. This core of EG is equal to plus 1. And ES is equal to plus 1 with a total score of plus 1. This core of FG is equal to plus 1. This core of FS is equal to plus 1 with a total score of plus 2. And this core of GS is equal to plus 1 with a total score of plus 1. and therefore the next total score is equal to plus 4, therefore total score that is s is equal to 4. Now we shall learn the second method for finding the score s. Since the ranks are signed to marks of English from A to H are in ascending order, the score of A B, A C, A D and so on up to A H are all plus 1. Now we shall discuss scores for ranks assigned to the marks in Hindi. To construct row 1 we see that for A there is one rank greater than 7 on its right that is 8, therefore we assign the score of plus 1 to it. Now for B in rank 2 there are 5 ranks greater than 2 on its right that is 5, 3, 4, 6 and 8, therefore we assign the score of plus 5 to it. Similarly for C in rank 5 there are 2 ranks greater than 5 on its right that is 6 and 8, therefore we assign the score of plus 2 to it. For D in rank 3 there are 3 ranks greater than 3 on its right, therefore we assign the score of plus 3 to it. Similarly these scores given to E, F, G and H are plus 2, plus 2, plus 1 and 0 respectively. Now to construct row 2 we have for A in rank Y there are 6 ranks less than 7 on its right, therefore we assign the score of minus 6 to it. Similarly for B in rank Y that is 2 there is one rank less than 2 on its right, therefore we assign the score of minus 1 to it. For C in rank Y that is 5 there are 3 ranks less than 5 on its right that is 3, 4 and 1, therefore we assign the score of minus 3 to it. Similarly we assign the score of minus 1 to D, minus 1 to E, 0 to F, 0 to G and 0 to H. To get row 3 we add the scores of row 1 and row 2 and we get 1 minus 6 that is minus 5 for A, for B we have plus 1 minus 5 that is 4, for C we have plus 2 minus 3 that is minus of 1, for B it is plus 3 minus 1 that is plus 2, for E we have plus 2 minus 1 that is 1, for F we have plus 2 plus 0 that is plus 2, So g we have plus 1 plus 0 that is plus 1 and for h it is 0 plus 0 that is 0 and the total of row 3 gives the total scores that is total score s is equal to minus 5 plus 4 minus 1 plus 2 plus 1 plus 2 plus 1 plus 0 which is equal to plus 4 therefore, kinders coefficient of Ram correlation which is given by tau is equal to twice of s upon n into n minus 1 so we have twice of s and s is equal to 4 therefore 2 into 4 upon and the value of n is given as 8 so we have 8 into 8 minus 1 which is equal to 2 into 4 that is 8 upon 8 into 7 so we have 1 upon 7 which is equal to 0.143 therefore kinders coefficient of Ram correlation tau is equal to 0.143 which is the required answer this completes our session hope you enjoyed this session