 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says, find the following integral, that is integral of secant square x divided by cosecant square x dx. So let us see the solution to this question. We have to find integral of secant square x divided by cosecant square x dx. This can be written as integral of 1 by cos square x because secant square x or we can say secant x is equal to 1 by cos x and this divided by cosecant square x that means into 1 by sine square x that goes to the numerator and we get this because cosecant x is equal to 1 by sine x into dx. So here we get integral of sine square x by cos square x dx. We know that tan x is equal to sine x by cos x. So tan square x will be equal to sine square x by cos square x. So we get this. Now we know that tan square x is equal to secant square x minus 1. Therefore we can write this as integral of secant square x minus 1 into dx. On separating these two terms, we get integral of secant square x dx minus integral of 1 dx. Now we know that integral of secant square x is equal to tan x plus c and we know that integral of x raise to the power n dx is equal to x raise to the power n plus 1 divided by n plus 1 plus a constant c where n is not equal to minus 1. So using these two, we can say that this is equal to tan x minus x plus a constant c. Now this in the second integral, we see that 1 is same as x raise to the power 0. So putting n equal to 0 in this formula, we get this. So our answer to this question is tan x minus x plus c. I hope that you understood the question and enjoyed the session. Have a good day.