 Hi, and welcome to the session. Let us discuss the following question. The question says, insert two numbers between 3 and 81 so that the resulting sequence is GP. Let's now begin with the solution. Let G1, G2, the two numbers between 3 and 81, G1, G2, 81 is a GP. Of the GP is 81, that means T4 is equal to 81. And this implies A into R to the power 3 is equal to 81. And in the question, first term that is A is equal to 3. So this implies 3 into R to the power 3 is equal to 81. And this implies R cube is equal to 27. And this implies R is equal to 3. Now since A is the first term and R is the common ratio, therefore the second term, that is G1 is equal to A into R. Now A is 3 and R is also 3. So this is equal to 9. And G2 is equal to AR square. A is equal to 3 and R is equal to 3. So we have 3 into 3 square and this is equal to 27. Hence the required two numbers are 9 and 27. This is our required answer. So this completes this session. Bye and take care.