 OK, let's try this one, which is the same problem as that last one, except instead of multiplying, we're adding. So it's going to be different, significant, figurables. So remember when you're doing addition of significant figures, you have to go to the number that has the least amount of significant figures after the decimal point. So in order to do that, you want to effectively find a common multiplier for all of the figures. So this one has 10 to the 6, this one has 10 to the 5, this one has 10 to the 5, so you probably want to change this one to 10 to the 5 as well. So when you do that, what you get is you're going to move your decimal point over to here, and then that's going to be 10 to the 5. So in other words, you're going to have 12.3 times 10 to the 5. So now the easiest way to do this, since they're all of that common 10 to the 5, is you can do how we did them in class, just add them up relative to their decimal point. So when we do that, we get 12.3. Now remember, we want to put the decimal point right underneath this first one, 8.35 and 5.39. So all of these are to the common times 10 to the 5. So we really don't have to worry about that portion of the answer because it's going to be times 10 to the 5 as well. So when we do this, we have to realize that this one only has one behind that decimal. These have two, so the answer is only going to have one behind the decimal. So 12.3 plus 8.35, we're going to get 26.0 and then at 4, which is next, it's going to not be there because we only want to get one decimal. So the 3 in this doesn't really have to do with each having three significant figures. So the answer is three significant figures. Does that make sense? So the answer, effectively, would be 26.0 times 10. Are there any questions on that? Again, remember to get them to the common factor. This one's kind of a messed up problem because of that O, so don't. I hope it doesn't to mess you guys up too.