 Hello and welcome to the session. In this session, we discussed the following question which says, find the area of a regular pentagon whose each side is 4 centimeters long and the radius of the inscribed circle is 5 centimeters. Before proceeding with the solution, let's recall the formula. For the area of a regular polygon of n sides, this is equal to n upon 2 into a into r square units. Where we have this n is the number of sides of the regular polygon. A is the length of each side of regular polygon. R is the radius of the inscribed circle. This is the key idea to be used for this question. Now let's move on to the solution. Now we are given a regular pentagon. So in a regular pentagon, we have n that is the number of sides is equal to 5. And we are given that each side is 4 centimeters long. So we say that we have a is equal to 4 centimeters. And also we have that the radius of the inscribed circle is 5 centimeters. So that means r is equal to 5 centimeters. Now we have the area of the regular pentagon is equal to n upon 2 into a into r square units. We put the value for n, a and r. So this is equal to 5 upon 2 into 4 into 5 centimeters square. Now 2, 2 times is 4. So this is equal to 5 into 2 into 5 centimeters square which is equal to 50 centimeters square. So the area of regular pentagon is 50 centimeters square whose side is of measure 4 centimeters. So final answer is 50 centimeters square. This completes the session. Hope you have understood the solution for this question.