 Vsih najboljih izgledaj je tudi všeč, ker smo zeločili kvantomekaniki, ok, menej ljudi, zeločili zeločiti polimetriče in polimetriče algebom in zeločili, kako je tudi kvantomekaniki zeločili, je tudi, da je nekaj zeločil in ki je vzeločil tudi. If you apply some concept in zelo se počutite po vseh kubitih, da se počutite počutiti, in da se počutite počutiti na 2 kubitih, in zelo se počutite. Zelo smo tudi ozvori korelacijov, in smo počutili, kako počutili korelacijov po vseh in vseh in vseh in vseh in potem smo počutili tudi tabu zelo da je tako doobošljeno, da je se zelo izgleda z Alice Tubo. Pa, da nekaj, da sem se pričačila, da je to dobrojne kar. Sredno je to dobrojno, da je to dobrojne kar. Srečno je to dobrojno, da je to dobrojne kar. In maybe I concluded by saying that to a computational scientist who is used to get to the last digit, except result to see that in running on the true computer you get 0457 instead of 05, and this is a good thing, is kind of a shock. And I'm really looking forward to the consequences of that on our society. Thank you very much. So, hi, I'm Peter, and I study physics as well, but it's never been as far as it gets in computing and other stuff, that is gauge theory. And so we were quite thankful to Katarina, who knew quite well about the theory. So let us just look at what we have done in this short time. We hope to manage more. So we just did with tutorial number one and tutorial number two. In tutorial number one there we have checked how the excited state decays. So you would typically think that the decays in exponential fashion. So the excited state you get with applying x to the ground state. And then what you do is you just apply it up to 38 times, more often if it's not possible. And then you check how the decay actually happens. And usually it should decay. So what you see on the y-axis is the overlap essentially with the first excited state. Like the percentage of how much it is excited. And you see that it should actually go to zero, but you just see the beginning of the exponential decay, where we cannot really see whether it is exponential or not, but we can imagine that it will be. In tutorial number two what we had to do was to entangle qubits. So one state we had to generate was the superposition, one over spirit of two, one zero plus zero one. And this we tried to realize by first having, by applying h to one ground state, to be equally in both. If you think about the best here. And the other one should have been excited, so that we could get the one in the other state. I'm not so sure about, but I'm making sense right now. In any way you had to use the C naught. And then what you have seen is that, so you are in the states either one zero or zero one, which is shown in the upper part. And then we also have to correlate the zero zero bits, so we want them essentially, when they slip from zero to one or from one to zero, we want them to always slip together and you also see it realized here. If it wouldn't be entangled, then you would have an equal distribution. What we also checked was whether there is a difference in applying x, like twice x should be the identity, or whether this leads to a different result than simply applying the identity, like just checking whether the operation that we are allowed to do in this interface whether they somehow differ. So we thought that applying xx would lead to more error than applying the identity. So what we checked was, which was not really quickly arranged, but essentially xx on the ground state would mean that we should, sorry, I think, it's the identity, so you see usually it stays in zero zero. In some cases, however, the first bit remained in one zero, and when you use the identity, it's essentially the same outcome, qualitatively, the numbers differ a bit. We thought that using identity is better than xx, but it is not. This is... All right, so I guess this was it in the short amount of time, and we really enjoyed working with the interface, because it's quite intuitive. Okay, thank you. So good afternoon, everybody. So our group worked on the hydrogen molecule. So the idea is basically that we have two atoms of hydrogen which comes with one electron, and these electrons can go from one orbiter to another and also interact between each other. There is one degree of freedom, but these two atoms are separated by a length r. And so this can change. Basically, the Hamiltonian can be rewritten in this form. Of course, the very beginning is worse than this, because you have to consider all these directions. But basically, it boils down to this, and we will need to actually compute the expectation value of only the value of the origins to then make use of the variational principle to compute the ground state energy, which will be given by this formula, and where we actually have another degree of freedom, which is this variable theta that we changed. So we actually try to reproduce what we did in this paper, where basically here it's the value of theta, and then we see these observations, the expectation value. And in this graph, there is the over three parameter r. So from this, we should be able to actually compute the ground state energy. So this is actually the experiment that they did. So they applied full sequence of pulses to reproduce the mechanics beyond this. And this is actually another way that this sequence could be written with such operations. And we are actually interested in reproducing these results with quantum experiments. So we have to translate these operations into what can be done with quantum experiments. So basically, probably against x, y, z, tofali gates, and other more gates, and so on. So we actually have to replace them. And this is actually what these could look like. So we just have to do the map. And we unfortunately didn't have time to go to the very end. But if you are to use this circuit and then modify the way you measure to actually compute the correlations, so the expectation value of x, x, y, y, z, z, and so on, we then be able to take all of these into the Newtonian and compute the fundamental energy. That's it. Okay. Thank you very much. So we were actually working on the upside, za vsej ultimi teželni tutočel. Zato se zelo pošličil, nekaj sem vrteva, kako došliš, da se kanacimo vboje, ki so se vse nekaj, ki všliš, ki se nekaj, in pa v teh da so neko šel. Zato se sem začel, da smo je tudi začeli, ki se niko nekaj, da smo nekaj, da smo nekaj, ki so nekaj, Ne biti nič? Volj! Po zelo pripočenju, da v tudi predetnem četvo je najbolj pojavlju in prienočnjo evočenje za ISO 0. Vz tago želimo početi risks za srkredne objevare, in to nešpevno načešlja. So ja začela, ko ne pa tako prihlevačno Sadno. Da. Také. Er, tako, bilo čakulj vznik, da bo zeločilo, da je treba bila prijevare. Zelo, moja ko행ya. To je tudi, da bilo dobro exprimenju experiment on the GHZ state. And it was stated in the tutorial defining three connected systems with X and Y that can take values from class minus one, and then trying to find the solution to equations which unfortunately we forgot to put here, but they look like x, y, y, x, y in so on equals to one, while x, x, x would be equals to minus one, which in classical terms is not solvable, because if you just multiply the first three equations, all the y's will go out because they're squared, and you will see that x, x, x can only be equal to one. Now, the quantum nature of these qubits in this case allow us to actually find the solution because it seems an unsolvable problem. Here you can see the scheme. The one in blue is the preparation of the state mentioned here, and for this state we measured the following three things, like x, x, x, so, for example, here, the x values in this table, but the scheme is shown in x, y, y, but here it's x. The different variations, you can imagine the azir scheme, there is all the probability together in this room here, and then what you see is that the highest probability are where x is equal to minus one, so the combinations with a odd number of ones. And for, we can calculate all the rest, basically the same table, we get the mean value, and we get the answer, which is here. We found that our system is deep in technology. Hello again. I also want to thank for the possibility that we could come here. You may have to say that our background was not physics or we were electrical engineers, and we had a great opportunity to somehow go back and travel in time somehow to our other red studies where we had some quantum mechanics, but not so much, so we spent a lot of time working with the tutorials that were online, and we found them quite helpful. It's really nice with the interface that you have to try these things out, also with the examples that you provided, but this also costs quite some time, so we were working on these tutorials and then found out that we didn't start the exercise yet. So we really did that in a short amount of time, but we were also working on the same two examples that you guys presented, and tried to first figure out the T1 decay time, which you will see here, so we had a couple of samples with a different amount of idle gates in between, and we tried to fit the curve to that in order to figure out what the decay time is in terms of gates or gate delays. Now, because we do not have so many samples here, I'm not sure whether it is really accurate, but we had something which is in the order of 30 gates. I don't know whether that is correct or not. That's the 27, so not around 30. After 60. Yes, but the error is quite large. We should maybe not take this number, let's take this number with a grain of salt and let's just say we need more data to have it more accurately, or have a more accurate number, but yeah. And then the second example, we do not have a picture for that, but we actually also saw that if you correlate a qubit, which is in superposition, with a qubit that is not in superposition with this XOR gate, you basically see that two states have a probability of almost 50%, and the others are very, very small probability to be, which is basically just a matter of error. Thank you. And among the things that we all did and tried to kind of investigate, I wanted to share an interesting result, maybe that was not mentioned so far. So here, I tried to do quickly another comparison, but I think the process went down. But I did kind of this ten idle gates on every processor at the same time. And just to see where the system ends up being at the end. And so the chance you're going to get, you know, you're processing the same state, you put it after ten rounds is 50%, more or less, which I guess makes sense, given that I think I saw similar numbers that a possibility that a single qubit just flips of the order of 5% or something like that in ten idle steps. Then you add some less reliable qubits that are there in one of them, which are, by the way, supposed to be enough, I mean, by the specs, they are supposed to be very similar, but these 4 and 5 seem to be very more often. So you end up with this large error rate. And you could imagine that it kind of scales with the number of qubits it tries to run. So that's maybe one thing to think about. All right? It's more or less it.