 Hello and welcome to this session. Let us understand the following problem today. Find the value of x if determinant 2345 is equal to x32x5. Now let us write this equation given to us as determinant 2345 is equal to determinant x32x5. Now first consider LHS is equal to where we have 2345 which on solving will give 10 minus 12 which is equal to minus 2. Now consider determinant on right hand side which is x32x5 which on solving will give 10 minus 12 which on solving will give 5x minus 6x which is equal to minus x. Now equating LHS is equal to RHS. So we get minus x is equal to minus 2 which implies x is equal to 2. Therefore the required value of x is x is equal to 2. I hope you understood the problem. Bye and have a nice day.