 Okay, so let's try this one so what we're looking at is the reaction of chromic acid with these different Benzene derivatives and benzene itself If you recall We react chromic acid with a benzene derivative, right at the benzylic position it will Make the derivative into a carboxylic acid But you have to have certain properties at that benzylic position. Okay, so since benzene itself Doesn't have a benzylic carbon, right? It doesn't have a carbon out here attached to the ring. There's not going to be any reaction When you put chromic acid So if you look here, we've got a benzylic carbon In fact, we've got a benzylic carbon there Got a benzylic carbon there, and we've got a benzylic carbon there What you need to Get the product that you're expecting and again remember you don't need to know the mechanism of this Which I don't Think is really fully understood anyways Okay, so that's the product you would expect and that's the product you get Okay, and in fact the same thing happens here. Do we get that product in both of those places whether it be the benzylic carbon have only the One carbon and the fennel ring coming off Or two carbons, so tertiary or secondary if you will Um, so if you get to a quaternary benzylic carbon that will also have no reaction So hopefully you guys can think of what's going on, right? But what's happening is of course We're at that secondary benzylic carbon, right? It's got those two ages there Okay, those are being removed oxidized. You know this carbon is being oxidized To the carboxylic acid or benzylic acid Same thing here, right? We've got these hydrogen that allows the oxidation to occur Okay, here. We've only got methyl groups or an ethyl group to alkyl groups at the quaternary carbon So since there's no hydrogens no reaction, so everybody okay with that The same thing is true with potassium permanganate to the for past potassium permanganate Oh, do all of these have that right here, let's see Let's just do methyl Patterns is that you have the benzyl of carbon and you have a high So do we have a benzyl of carbon? Yes, in this case It's the primary benzyl carbon with the three hydrogens on it So yes, this will be oxidized as well to the same product That's a good question. Any other question makes sense, right? So as long as we have access of it, then we can do it as many times Yeah, so so yeah, you can see if you go down to some of the problems, right? Let's just say we've got something. I don't know like this What's gonna happen make sense Doesn't matter how long the chains Well, only thing that matters is if you've got that a hydrogen All right, this one no hydrogen so we ain't gonna what this one no benzyl of carbon so it ain't gonna work So is that What's gonna be the product I need to be teaching them the place with a bunch of tall people Is that everybody's question Okay, cool Okay guys