 Hello and welcome to the session. I am Asha and I am going to help you for solve the following question which says find the sum of n terms of the AP whose k term is 5k plus 1. Let us start with the solution. So let k term ak, so this is given to us as ak plus 1. The first let k is equal to 1 then the first term will be 5 into 1 plus 1 which is equal to 6. Now let k is equal to 2 then a2 will be equal to 5 into 2 plus 1 which is equal to 11. Further let k is equal to 3 so the supplies a3 is equal to 5 into 3 plus 1 which is equal to 16. Therefore ap series is 6, 11, 16 and so on. We find that the first term and the common difference is equal to 11 minus 6 which is equal to 5. And according to the question we have to find the sum of n terms of the given AP. So the sum of n terms will be n upon 2 into 2a plus n minus 1 into d is equal to n upon 2 into 2a is 6 plus n minus 1 into d is 5. So this is further equal to n upon 2 12 plus 5n minus 5 which is equal to n upon 2 5n plus 7. The sum of n terms is equal to n upon 2 into 5n plus 7. So this completes the solution. Take care and bye for now.