 hello and welcome to the session let's work out the following problem it says from a window 60 meters high above the ground of a house in a street the angles of elevation and depression of the top and the foot of another house on the opposite side of the street are 60 degrees and 45 degrees show that the height of the opposite house is 60 into 1 plus under the root 3 so let's now move on to the solution we are given that a window which is at a height of 60 meter let this be a we are given that the angle of elevation and depression of the top and foot of the another house are 60 degrees and 45 degrees respectively so let e be the another house so let a be the window which is at a height of 60 meter and c e be the another house now a b is 60 meter which is same as c d right and also if this angle is 45 degrees this angle will also be 45 degrees as bc is parallel to ad and these are alternate angles so this angle is equal to this angle so now in right triangle a bc a b upon bc that is perpendicular upon base is equal to 1045 degrees right now a b is 60 bc and 1045 degrees is 1 so this implies bc is equal to 60 that is this distance is also 60 meter so this implies bc which is equal to 60 meter ad is also equal to bc now we know that a b is equal to cd and cd is 60 meter now we need to know the length d e so now in right triangle a d e d e upon ad that is perpendicular upon base is equal to tan 60 degrees now again d e upon ad which is 60 meter is equal to tan 60 degrees which is root 3 so this implies d e is equal to 60 into root 3 now c e which is the height of the another house is equal to d e plus dc or cd now d e is 60 root 3 cd is 60 so we have taking 60 common we have 60 into root 3 plus 1 hence the height of opposite house is equal to 60 into 1 plus root 3 so this completes the question and the session by franautik here have a good day