 Hi and how are you all today? I am Priyanka and let us discuss the following question. It says solve the inequality for real x. The inequality given to us is 3 bracket x minus 2 bracket close divided by 5 less than equal to 5 bracket 2 minus x bracket close divided by 3. So let us solve this inequality for real x. As we can see that there are brackets. So let us remove the brackets first. So we have 3x minus 6 divided by 5 less than equal to 10 minus 5x divided by 3. Now on multiplying both the sides by 5 we have 3x minus 6 multiplied by 5 divided by 5 less than equal to 10 minus 5x divided by 3 multiplied by 5 after simplifying the simplification we have 3x minus 6 less than equal to 50 minus 25x divided by 3. Now on multiplying both the sides by 3 we have 9x minus 18 is less than equal to 50 minus 25x. On subtracting 9x from both the sides we have 9x minus 18 minus 9x less than equal to 50 minus 25x minus 9x. On solving we are left with minus 18 is less than equal to 50 minus 34x. Now on subtracting 50 from both the sides we have minus 18 minus 50 is less than equal to 50 minus 34x minus 50. After simplification we have minus 68 is less than equal to minus 34x. On multiplying both the sides with a negative number that is minus 1 we have 68 and now we will be changing the sign of inequality as we have multiplied both the sides by a negative number we have 68 is greater than equal to 34x. Dividing both the sides by 34 we have 68 divided by 34 is greater than equal to 34x divided by 34. After simplifying we have 2 is greater than equal to x or we can say that x is less than equal to 2. So for real x the solution set consist of all the real numbers that is less than equal to 2. So it is minus infinity to 2 open interval on minus infinity side and closed interval to the 2 side. So this completes the question bye for now.