 Hi, and welcome to the session. I am Shashi and I am going to help you to solve the following question. Question is, using elementary transformations, find the inverse of each of the matrices. If it exists, the given matrices 2, minus 6, 1, minus 2. Let us start with the solution now. Let A is equal to matrix 2, minus 6, 1, minus 2. Now, to find the inverse by elementary transformation, row transformation method, we will write A is equal to I A, where I is the identity matrix or we can write 2, minus 6, 1, minus 2 is equal to matrix 1, 0, 0, 1 multiplied by A. Now, we will apply a sequence of row operations simultaneously on the left-hand side and the matrix I, that is the identity matrix on the right-hand side. The row operations will take place till we obtain identity matrix on the left-hand side. Now, to make this element equal to 1, we will apply an R1 row operation 1 upon 2, R1. So, we can write applying R1 row operation 1 upon 2, R1. We get 1, minus 3, 1, minus 2, matrix is equal to 1 upon 2, 0, 0, 1 matrix multiplied by A. Now, to make this element equal to 0, we will apply on R2 row operation R2 minus R1. So, we can write applying on R2 row operation R2 minus R1, we get matrix 1 minus 3, 0, 1 is equal to matrix 1 upon 2, 0, minus 1 upon 2, 1 multiplied by A. Now, to make this element equal to 0, we will apply on R1 row operation R1 plus 3 R2. So, we can write applying on R1 row operation R1 plus 3 R2, we get matrix 1, 0, 0, 1 is equal to matrix minus 1, 3, minus 1 upon 2, 1 multiplied by A. We know identity matrix is equal to A inverse multiplied by A. Now, comparing these two expressions we get A inverse is equal to matrix minus 1, 3, minus 1 upon 2, 1. So, our required inverse is given by the matrix minus 1, 3, minus 1 upon 2, 1. This completes the session. Hope you enjoyed the session. Take care and goodbye.