 Hi, and welcome to the session. Let us discuss the following question which says, construct a triangle ABC in which AB is equal to 6.5 centimeters, angle B is equal to 60 degrees and VC is equal to 5.5 centimeters. Also construct a triangle AB-C- similar to triangle ABC whose each side is 3 by 2 times the corresponding side of triangle ABC. Let's see its solution. First of all we need to draw the triangle ABC in which AB is equal to 6.5 centimeters, angle B is equal to 60 degrees and VC is equal to 5.5 centimeters. So let us draw a rough sketch of the triangle ABC. Suppose we have triangle ABC and AB is 6.5 centimeters, angle B is equal to 60 degrees and VC is equal to 5.5 centimeters. So now from this rough sketch we can get a lot of help to construct the triangle ABC. So first of all let us draw a line segment AB of length 6.5 centimeters. So here we have drawn the line segment AB of length 6.5 centimeters. Now let us write the steps of construction side by side. So our first step of construction will be draw a line segment AB equal to 6.5 centimeters. Now let us draw an angle of 60 degrees at point B. So here angle XBA is equal to 60 degrees. Thus our second step of construction will be draw angle XBA equal to 60 degrees. Now we have BC equal to 5.5 centimeters. So from point B we will draw an arc of radius 5.5 centimeters to cut the range BX at point C. So here we have drawn the arc and this is the point C. Now let us write our third step of construction that is with B as center and radius 5.5 centimeters draw an arc to cut range BX at point C. And now to get the triangle ABC we will join AC like this. So our fourth step of construction is join AC. So now we got the triangle ABC. Now we need to construct a triangle AB dash C dash similar to triangle ABC whose each side is 3 by 2 times the corresponding sides of triangle ABC. So for this first of all draw array AY making an acute angle with AB on this side that is the side opposite to the vertex C. So here we have drawn the array AY. Now let us write the fifth step of construction that is draw array AY making an acute angle with line segment AB on the side opposite to vertex C. Now we are given that each side of the triangle AB dash C dash is 3 by 2 times of the corresponding sides of triangle ABC. Here among 3 and 2 3 is greater. So on array AY we will locate 3 points A1 A2 and A3 such that A A1 will be equal to A1 A2 will be equal to A2 A3. So here we have located 3 points A1 A2 and A3 such that A A1 is equal to A1 A2 is equal to A2 A3. And here our sixth step of construction will be locate 3 points A1 A2 and A3 on array AY such that A A1 is equal to A1 A2 is equal to A2 A3. Now from 3 and 2 2 is smaller. So here join the second point that is A2 to the point V like this and thus the seventh step of construction is join A2 V. Next we will draw a line through A3 parallel to the line A2 V to intersect the extended line segment AB at point B dash like this. So this is the point B dash. Let us write the eighth step of construction that will be draw a line through A3 parallel A2 B intersecting the extended line segment AB at point B dash. Similarly we will draw a line through B dash parallel to the line segment BC intersecting the extended line segment AC at point C dash like this. So this is the point C dash and here BC dash is parallel to BC. So as the ninth step draw a line through B dash parallel BC intersecting the extended line segment AC at point C dash. So here AB dash C dash is the required triangle which is similar to the triangle ABC. Triangle AB dash C dash is the required triangle. So here first of all we have constructed the triangle ABC and then we have constructed a triangle AB dash C dash similar to the triangle ABC. With this we finished this session. Hope you have understood the construction. Goodbye, take care and have a nice day.