 Hello and welcome to the session. My name is Asha and I am going to help you with the following question that says Find the derivative of the following functions. It is to be understood that a, b, c, d, p, q, r and s are fixed non-zero constants and m and n are integers. 6th one is 1 plus 1 upon x upon 1 minus 1 upon x. Let's start with the solution and let us denote the given function by y. So, y is equal to 1 plus 1 upon x upon 1 minus 1 upon x. Now, simplifying it further, first solving the numerator, x is the LCM upon again x LCM and the numerator we have x minus 1. Now, we have x plus 1 upon x into x upon x minus 1. On cancelling we have x plus 1 upon x minus 1. Therefore, y is equal to x plus 1 upon x minus 1. Now, it is fine. Derivative of y that is dy upon dx. So, we have dx of x plus 1 into x minus 1 minus x plus 1 into derivative of x minus 1 upon x minus 1 whole square. And this is by the quotient rule which we have done in earlier quotient also. And this is further equal to now derivative of x plus 1 with respect to x is 1 since derivative of constant is 0 and derivative of x is 1 into x minus 1 minus x plus 1 into derivative of x minus 1 is again 1 since derivative of x is 1 and derivative of minus 1 is 0. Right in the denominator we have x minus 1 whole square. Now, this is further equal to x minus 1 minus x minus 1 upon x minus 1 whole square. Now, plus x minus x on cancelling we are left with minus 2 upon x minus 1 whole square. Now, the given function is 1 plus 1 upon x upon 1 minus 1 upon x. Now, for x is equal to 0 this function is not defined since 1 upon 0 is not defined and also if we take x is equal to 1 then in the denominator we get 0 and for the quotient rule the derivative of the quotient of 2 functions is applied if the denominator is non-zero. Therefore, for x is equal to 0 and x is equal to 1 the function is not defined. Hence, we can say that this function is defined for all the values of x except x is equal to 0 and 1. Right? So, for these two values this function is not defined hence the answer is the derivative of the given function is minus 2 upon x minus 1 whole square for x not equal to 0 and 1. So, this completes the session. Bye and take care.