 Hello and welcome to the session. In this session we will discuss the question which says that card spelling numbers 1, 3, 5 and so on up to 35 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card bearing, first part, applied number less than 15, second part, a number, divisible by 3 and 5. Now before starting the solution of this question, we should know our result. And that is probability of an event e that is Pae is equal to number of outcomes favorable to e over number possible outcomes. Now this result will work out as a key idea for solving out this question. And now we will start with the solution. It is given that a card is drawn at random from a bag containing the cards bearing numbers 1, 3, 5 and so on up to 35. That means that the bag is containing the cards bearing all numbers from 1 to 35. Now in an event at random from a bag containing same numbers 1, 3, 5 and so on up to 35, the total number of possible outcomes is 18. That is the cards bearing the numbers 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33 and 35. Now in the first part we have to find the probability of getting a card bearing a prime number less than 15. Now let e the event of getting the card bearing a prime number less than 15. Then the number of outcomes favorable to e 5 that is the cards bearing less than 15. And that are 3, 5, 7, 11 and 13. So 3, 5, 7, 11 and 13. Now by using the result which is given in the key idea, we can find the probability of the event e by using this formula. Now probability of the event e that is probability of getting the card bearing a prime number less than 15 is equal to number of outcomes favorable to e which is 5 over total number of possible outcomes which is 18. So this will be equal to number of outcomes favorable to e that is 5 over total number of possible outcomes that is 18. So probability of getting a card bearing a prime number less than 15 is 5 by 18. Now in the second part we have to find out the probability of getting the card bearing a number divisible by 3 and 5. Now in the second part let e the event of getting the card bearing a number divisible by 3 and 5. So probability of getting the card which is bearing a number divisible by h that is 1 which is 18. So this will be equal to number of outcomes favorable to h that is 1 over total number of possible outcomes which is 18. This is the solution of the given question and that's all for this session. Hope you all have enjoyed the session.