 Hello and welcome to the session. Let us understand the following question today. Is the falling pair of linear equation has unique solution, no solution or infinitely many solutions? In case there is a unique solution, find it by using trans multiplication method. We have 3x-5y is equal to 20 and 6x-10y is equal to 40. Now that is why the solution, the given equations are x-5y is equal to 20 or 3x-5y-20 is equal to 0 and 6x-10y is equal to 40 or 6x-10y-40 is equal to 0. Now comparing the equations with a1x plus b1y plus c1 is equal to 0 and a2x plus b2y plus c2 is equal to 0. So we have a1 is equal to 3, a2 is equal to 6, b1 is equal to minus 5, b2 is equal to minus 10, c1 is equal to minus 20 and c2 is equal to minus 40. Now a1 by a2 is equal to 3 by 6 which is equal to 1 by 2, b1 by b2 is equal to minus 5 by minus 10 which is equal to 1 by 2 and c1 by c2 is equal to minus 20 by minus 40 which is equal to 1 by 2. Now we can see that a1 by a2 is equal to b1 by b2 is equal to c1 by c2 which implies infinitely many solutions. Hence the given system of equations has infinitely many solutions and this is our required answer. I hope you understood the problem. Bye and have a nice day.