 Hi and welcome to the session the question says find the value of other five trigonometric functions Now here the value which is given to us is sine x is equal to 3 by 5 and x lies in the second quadrant So let us start with our solution Now here we're given the value of sine x as 3 by 5, right? so we can easily find out the value of cosec x that is 1 by sine x that means 5 by 3 then One of the identities that is known to us is cos square x plus sine square x is equal to 1 Let us substitute the value of sine x as 3 by 5 and Find out the value of cos square x First and then cos x so after simplification We have the value of cos square x as Plus minus 4 by 5, but as we know that x lies in the second quadrant So that means its value will be negative since x lies in second quadrant therefore Cos x is equal to minus 4 by 5 So we can find sec x that is 1 divided by cos x which will give us minus 5 by 4 at its value further the value of tan x is sine x divided by Cos x that will be the value of Cos x is minus 4 by 5 the value of sine x is 3 by 5 so we have the value of tan x as minus 3 by 4 and we are left with finding out the value of Cortex that is 1 divided by Tan x that is minus 4 by 3 So the solution is Cos x value is 5 by 3 Cos x is minus 4 by 5 whereas Sec x minus 5 by 4 the value of tan x Was found to be minus 3 by 4 Whereas the value of Cortex is minus 4 by 3 wait, so this completes the question that was given to us. I hope you enjoyed the session bye for now