 Hi and welcome to the session. Let's work out the following question. The question says, find the equation of the line passing through the point P, that is minus 1, 3, minus 2, and perpendicular to the line z upon 1 equals to y upon 2 equals to z upon 3, and x plus 2 upon minus 3 is equal to y minus 1 upon 2 is equal to z plus 1 divided by 5. So, let us see the solution to this question. First of all, we see that equation of the line passing through minus 1, 3, minus 2 is x plus 1 upon a is equal to y minus 3 upon b is equal to z plus 2 upon c. This we call equation 1. Now if it is perpendicular to the lines x upon 1 equal to y upon 2 equals to z upon 3, and x plus 2 divided by minus 3 is equal to y minus 1 upon 2 equals to z plus 1 upon 5, therefore direction ratios of first line are 1, 2, 3, therefore a plus 2v plus 3c equals to 0, and this we call equation 2, and direction ratios of second line are minus 3 to 5, therefore minus 3a plus 2v plus 5c is equal to 0, and this we call equation 3. Now solving 2 and 3, we get a upon 10 minus 6 is equal to v upon 5 minus 9 is equal to, now this is minus v upon 5 minus 9, this is equal to c upon 2 minus 6, this implies a upon 4 is equal to minus v upon minus 4 is equal to c upon minus 4, or this also implies that a by 4 is equal to b by 4 is equal to c upon minus 4, or we can say that a is equal to 4, v is equal to 4 and c is equal to minus 4, now putting these values in first equation we get, x plus 1 divided by 4 is equal to y minus 3 divided by 4 is equal to z plus 2 divided by minus 4, which is the required equation of line. So our answer to this question is x plus 1 upon 4 is equal to y minus 3 upon 4 is equal to z plus 2 divided by minus 4, so I hope that you understood the solution and enjoyed the session, have a good day.