 Hello and welcome to the session. Today I will help you with the following question. The question says construct the following quadrilateral rhombus B E N D where B N is 5.6 cm and D E is 6.5 cm. Now before drawing the actual figure first let's have a look at the rough sketch of the quadrilateral B E N D. Where B N that is one diagonal of the rhombus is given to be 5.6 cm and the other diagonal D E is 6.5 cm. Now let's move on to the solution. Now we'll construct the rhombus step by step. Now visualizing the rough sketch of the rhombus B E N D a first step can be draw a line segment D E equal to 6.5 cm. So as you can see we have taken a high segment B E of 6.5 cm so we have got one diagonal of the rhombus B E N D. Now we will construct the other diagonal B N of the rhombus B E N D. And we know that the diagonals of the rhombus bisect each other and are perpendicular to each other. So in order to draw the other diagonal we will draw the perpendicular bisector of D E. And for this first we take D as the center and radius more than half of D E and make an arc on both sides of D E that is above D E and below D E. So our second step is with D as the center and radius more than half of D E we make arcs on both sides of D E. So as you can see we have drawn arcs on both sides of D E of radius more than 6.5 cm that is D E. In the same way taking E as the center and radius more than half of D E we make arcs intersecting the previous arcs. So our third step is taking E as the center and radius more than half of D E we draw arcs intersecting the previous arcs. So as you can see taking E as the center and radius more than half of D E we have made arcs which are intersecting the previous arcs. Now in the next step we join these points of intersection of the arcs. So our next step is join the points of intersection of the arcs. So we have joined the points of intersection of the arcs and we have named this line as X Y. This is the perpendicular bisector of the diagonal D E. Now let's mark this point as O. Now we are given that B N is 5.6 cm. So now our next step would be to locate the points B and N. So now to locate the point B what we do is with O as the center and radius equal to B N upon 2 and that is equal to 2.8 cm. We mark an arc on O X. So we have made an arc of radius 2.8 cm on O X. Now let's mark this point as B. In the same way we will mark an arc of radius 2.8 cm on O Y. So to locate the point N what we do is with O as the center and radius B N upon 2 and that is equal to 2.8 cm. We mark an arc on O Y. So we have made an arc on O Y of radius 2.8 cm. Now let's mark this point as N. Now we join the points B and D, B and E, D and N and N and E. So as to obtain the rhombus B, E and D. So now in the next step we join the points B and D, B and E and E. So as you can see we have joined the points B and D, B and E, N and D and N and E. So B E and D is the required rhombus where B N is 5.6 cm and D E is 6.5 cm. Hope you enjoyed the session. Have a good day.