 Hello and welcome to the session. My name is Mansi and I'm going to help you with the following question. The question says, integrate the following function that is x into secant square x. So let us start with the solution to this question. Let i be equal to integral of x secant square x dx. Now according to the i-late rule, we see that an algebraic function is given preference over the trigonometric function for becoming the first function. So this will be the first function, this will be the second function. Now we will integrate it by parts. So i will be equal to first function that is x into integral of second function that is secant square x dx minus integral of d by dx of first function that is x into integral of secant square x dx into dx. This will be equal to x into, now integral of secant square x dx is tan x minus integral of dx by dx will be 1 into tan x dx plus the constant now here we will have this much and this will be equal to x tan x of cos x because we see that integral of tan x dx is minus log cos x minus times the minus sign becomes positive. So our answer to the question is x tan x plus log of cos x plus c. So I hope that you understood the question and enjoyed the session. Have a good day.