Lec 9 | MIT 18.06 Linear Algebra, Spring 2005
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Good, I like that you share this video Independence, Basis, and Dimension., I wish success always
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Nice Video Independence, Basis, and Dimension That You Share , So Very Nice Thanks You
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I Really Like The Video Independence, Basis, and Dimension From Your
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Your Video Is Very Useful Sharing Independence, Basis, and Dimension.
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WAAAYYY Better than my Linear Algebra prof
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This lectures are so simple to understand.
The lectures that my professor of linear algebra give at my university are so difficult to understand even at the beginning because he doesn't explain in a language that a new student understand.
He start to write the role with symbols that i doesn't seen before and then prove all the theories without speaking what's going on before.
Thanks for all this lectures.
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If you guys find the determinant of the matrix, it shows Det = 1*(16-15) - 2*(8-6) + 3*(5-4) = 0. So the matrix is not linearly independent.
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What a guy!
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Thanks........
Praveen
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The second basis for R^3 is not a basis, since -(1,1,2)+2*(2,2,5)=(3,3,8); i.e., the vectors are not linearly independent.
Lemnirot 2 years ago 41
These lectures are so great. I am taking quantum mechanics and linear algebra is a large part of it. Looking at these helps review linear algebra and he is such a great teacher.
Thanks !!!
russelljbarry15 2 years ago 21