Senior Chemistry: Acids and Bases 12
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Uploader Comments (bannanaiscool)
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OH! so that's why we do that little subtraction!!!....to find the excess moles of stuff in solution which determines the ph....wow, the only chemistry teacher i have is on the internet...
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haha! INXS
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All Comments (16)
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@bannanaiscool s this all that i need to knoe in acids and bases???......m a 12th std student!
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You are fantastic!
like, big time.
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in XS i am using that from now on
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fooled ya this side! :) HAHA. chemguy you're like a billion times better than my chem teacher, she's horrible :( depending on your lessons now!
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chemguy i love u !!!!!!!!! i really do///
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You are saying that 0.1M of CH3COOH will fully disproportionate to give 0.1M of H3O+, but... isnt it a weak acid? so it doesnt 100% give 0.1M of H3O+? i am getting the idea that its like ur doing strong acid + strong base, but ur doing weak acid with base, so do you consider the weak acid a strong 1? thanks btw
Sulfhur1k 1 year ago
@Sulfhur1k No, I don't say that this weak acid will dissociate 100% but it will react with OH- 100%. There's a difference. OH- is such a strong base that it will completely remove the H+ from the weak acid.
Chemguy
bannanaiscool 1 year ago
The excess hydroxide will have such a higher concentration than what the conjugate base ion will produce of hydroxide in solution that you can disregard it.
Glad you we pondering this. It shows you get it!
Chemguy
bannanaiscool 3 years ago
When you say disregard 'it' you mean we disregard the conjugate base of the reaction and just get the ph of the excess NaOH which, because of it's higher concentration, will dominate the ph of the solution at the end of the reaction?
So the reaction itself only serves the purpose of using up an amount of the NaOH in order to reduce it's total amount and also dilute what's left in more solvent?
Monkmaney 2 years ago
Pretty much right! The excess NaOH will easily produce more OH- ion in solution than that very weak conjugate base ion of low concentration!
Chemguy
bannanaiscool 2 years ago