SGDQ bonus: SotN casual any% run in 23:42 by romscout

I was just showing off the new fastest reliable SS route for SotN during the Summer Games Done Quick bonus stream. -- Recorded live on Justin.tv - http://j-tv.me/q3LNqQ

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Gaming

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• justin.tv

[thebored14]

why do you always grab the health upgrade at 8:55 ?

[romscout]

@thebored14 the main reason is because I usually run the game with the in-game timer in mind, and grabbing those doesn't add to the in-game timer, making this faster than jumping over it as far as that's concerned. I grab it in races just because I'd rather have full health going into the colosseum in case I screw up.

[JDHyatt1989]

you should use power of sire

[romscout]

@JDHyatt1989 the animation's too long and it doesn't do much more than a buffalo star

[garrastar1]

Grrr... I can never do this in Symphony...that's why I decide to speedrun Harmony of Despair, because its much easier to speed run those chapters...

[romscout]

@garrastar1 if you're doing Harmony of Despair optimally, it's much harder now with all those crazy zips.

[RadonX9]

I take it that the name 'LOL DRAC' is what your Avatar is called? XD

[garrastar1]

@romscout even if it is, I can't do all those glitches you do in this. and the spells never want to work when they should for me..

[thebored14]

@romscout interesting

[MyOverflow]

@MyOverflow (continued)

Also, all of memory is stored in binary. It's just that hexadecimal E7 is a lot less monotonous than the binary 11100111 (both are the number 231 in decimal), and so that's why a lot of debugging tools use that instead. But, in order to understand the actual computer science behind this, it's a lot better to look at it in binary to see what is actually going on.

[RuroJiruries]

I missed the actual SGDQ run since it was so late in the night (here in the UK) to view it, so thanks for upping this bonus :P Legendary

[MyOverflow]

@MyOverflow (continued)

The reason you get 255 is because the item amount is stored in 1 byte of memory.

So, in memory, it's like this (in binary):

100000000

The last 8 0's are, together, the binary representation of the 1 byte item amount at 0. the 1 is something else in memory stored before the item's amount. Subtracting 1, you get

100000000 - 1 = 011111111.

The 1 in front goes to 0 to give the variable enough to subtract 1, then what's left is the binary for 255.