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Limit Comparison Test and Direct Comparison Test

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Uploaded by on Apr 12, 2008

Using the Limit Comparison Test to Determine if a series converges or diverges. For more free math videos, visit http://PatrickJMT.com

Austin Math Tutor, Austin Math Tutoring, Austin Algebra Tutor, Austin Calculus Tutor

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Uploader Comments (patrickJMT)

  • please make a video about solving improper integrals with the comparison test!!

  • @jennygallery ok, that sounds like a good idea

  • is there a video on solving improper integrals using the comparison test?

  • @SpnFan04 that is a good question

  • Patrick, this doesn't complement what you said about the Test for divergence, for the second example you said the limit = 2, and it converges. But the Test for Divergence states that if the limit is not = 0 then it diverges, our limit was not = 0 so how come it converges?

  • @ferasteddy this is not the test for divergence that i am using.

Top Comments

  • i went through your entire sequence/series playlist. LOVE YOU AND THANKS!

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  • I LOVE YOU!!!!!! I wish you were my calculus teacher

  • haha he says "a-subbinz" and "beesubinz"

  • Just learned this today and ONCE AGAIN, you saved my life!

  • Brilliant. Thanks.

  • Hey Patrick, my test is next week but I was wondering, whats the use of doing the limit of (a sub n) / (b sub n) if you end up only looking at what (b sub n) does in the end? Since (b sub n) converges in your example, why do we need to do all that other stuff? Also, what does the 2 mean? In my problem, I got that the limit when I divide mine is 1. I don't know what that means, lol. SO CONFUSED.

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