Separable differential equations 2

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Uploaded by on Aug 28, 2008

Another separable differential equation example.

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  • Are professors bothered by you being 10x more concise than they are?

  • you are def the man. thanks so much.

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  • I don't have to go to lecture ever again. Thank you so much.

  • you rock.

  • Test tomorrow, you just saved me

  • @zodei 'so ln(u(x))=p(x)', sry that was supposed to be 'ln(u(x))=integral(p(x))'... i was supposed to integrate both sides... the integral of u'(x)/u(x) is ln(u(x)) (due to the chain rule - just derive ln(u(x)) to check this) and i forgot to integrate the right hand side. in the next step i didn't make that mistake because i got u(x)=e^integral(p(x)). i realize these remarks can only be a hint to the actual solution but i still hope they are gonna be helpful.

  • @zodei difficult question... divide by tan(x) to obtain the standard form of this 1st order linear ODE: y'+p(x)*y=q(x); p(x)=cot(x), q(x)=csc(x). multiply both sides by an integrating factor u(x) to obtain u(x)*y'+p(x)*u(x)*y=q(x). why? if u(x) is chosen carefully the product rule will simplify this to [1.1] (u(x)*y)'=q(x). for that to work u'(x) has to be p(x)*u(x), so u'(x)/u(x)=p(x), so ln(u(x))=p(x), so u(x)=e^integral(p(x)). use this to calculate u(x). plug it into [1.1]. integrate [1.1].

  • hey! How you solve this tan x dy/dx + y = sec x? =D

  • @platazar MS Paint?

  • PLEASE WHAT'S THE NAME OF THIS SOFTWARE ?

  • y go to class for 50 mins when i can learn it in 5 mins, in my pj's

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