Integral of (sinx)^4cosxdx
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now take the integral of sin^4(x) without cos(x) next to it and post a vid for me
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ala kang kayapan nimal!
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very much a helpful video, thank you very much.
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@bmthnumber1 I'm sorry, at the end of my commentary I should have said: "The derivative of (sin(x))^4 (the term inside the parenthesis only -sinx-) is cos(x). Then, the criteria for using the formula is valid."
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There's actually a formula wich is easier to use in that case (and similars).
It's: f(x) * f ' (x) = f(x)^n+1 / n+1
In words: When you got a function wich is a product, in wich one of its terms happens to be the derivative of the other term, then, the integral solution will be the f(x) to the n+1 power (being n its actual power (4 in this case) ), divided by n+1.
We re-write the integral as I: sin(x)^4 * cos(x) dx
The derivative of sin(x) is cos(x). Aply the form: sin^5(x) / 5 + c
Solved.
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hahahahahahahahahahahahahahaha
ha -
Wow, why are people being so negative, we are all human we make mistakes and learn from them, this guy is doing us a favour by providing helpful videos, if you don't like these then just leave the video and don't leave negative feedback, ungrateful people...
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NERD
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really great idiot :D
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he just show the common mistakes like that.. hehehe
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the guy on the camera knows more than him
random19911004 3 years ago 6
hold up, did I do this right? LOL
juggy2008 3 years ago 5