Input is 12v 290mA. took about 8 hours to get it from 12.2v to the 13.3 it currently rests at. with that logic it should fully charge it to 12.6v from dead in about the same time. giving it more time to make it rest at 15v right now..
I dont really like doing this so much because im all about efficiency. this is not very efficient in terms output compared to input, because im sending around 300mA through the 28 awg and thats getting it warm.. BUT if i want to charge a battery really fast it gets it done.. the only reason for this in my opinion is because im pulse charging it with over the 25-100mA input i would prefer to give it.
this is a new 12v that has not been fully discharged once yet. it will charge beyond 16v and right now im seeing how high it will rise.
i notice that when it reaches about 15.3v it will settle at around 13.3v so im thinking if i let it get to around 17v it will rest at 15v.
i know a lot of people try to make motors that simply charge a battery like no tomorrow.. well just use a bedini and feed it a good current.. it may not be so efficient but it will get it done.
@egn83b well i usually have no problem simply running the backspikes back to the front, but it never seems to be enough to really make much difference. simply reverse dioding the charge batt directly from the coils does a good job of getting nothing but the spikes to go back to the front, totally reducing any direct shorts between front to back, but in that situation you are always just getting back an inductive negative spike which is never enough
Magneticitist 1 year ago
@Magneticitist I cant say because I have not seen it work with the setup I was talking about because I have theory but not experience with one to one trasnsformers. But yea it might just don't sure but a blocking diode to isolate the coil so it doesn't suck power could work.
egn83b 1 year ago
@egn83b i wondered the same thing but back then had no idea how to make a cap pulser, otherwise u are just shorting the run coil with the impedance of the 1:1 right?
Magneticitist 1 year ago
@egn83b its real but it always reads about 1.5v over the actual rest. so i usually try to get it to say about 15v on the meter before i know it will rest at 13.5v
Magneticitist 1 year ago
Seeing the meter go up as fast as it did would that be capacitive effect or a real current charge on the battery. I have messed with exciters charging up batteries and I always have disappoiting charge results after the battery rests.
egn83b 1 year ago
One thing I have always wondered is by using a one to one transformer with a batt cap or super cap will isolate the power supply from the battery and cause a self charge even with a bit of low impedance loss due to cap design flaw really charge and work off a single battery?
egn83b 1 year ago