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@RasmusLastname Hmm. I think I know where this confusion is, and I'll admit I'm partly at fault.
Out of interest, where (or, if it's in the video, when) did you get this idea of a "quantum of energy"? Was it an exact quote or did you paraphrase someone?
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@wreynolds1995 "In physics, a quantum (plural: quanta) is the minimum amount of any physical entity involved in an interaction" (Wikipedia) So, since they're all photons, shouldn't the quantum of light always be a specific energy level? I'm not saying you're wrong, I know you're right, I'm just trying to understand it better. It would be really helpful if you could answer ^^
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@RasmusLastname No. When we say "a quantum of energy," it's the same as when we say "a packet of light", see? It just means a little bundle of the stuff.
In fact, the greater the energy of the light, the greater the frequency of the light. Need proof? Handheld lasers. Red light has a greater wavelength (and so less energy) than green light, and same for green light and blue light; hence why red lasers aren't as dangerous as green lasers, and why green lasers cost more.
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lol "for all us english speakers" good one sixty symbols!
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If a photon is a quantum of energy how can they have different energy values? Isn't quantum sort of a minimum value?
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@UmlautBanana actually you do i think. it's just infintesimally small you don't really feel anything.
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this one was really boring for me until learning about the why the sky is blue
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Wait... if photons are particles, why don't you get a recoil force from, say, switching on a flashlight?
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No, she's from the US so she accidentally called it a flashlight, and he corrected her for the UK viewers who call it a torch.
photons have relativistic momentum.
using einstein's famous energy equation and adding the relativistic momentum term (giving the general energy expression):
E^2 = (m^2) x (c^4) + (p^2) x (c^2)
E is energy, m is rest mass, p is momentum, c is speed of light. photons have zero mass so E = pc. the E of photons exist in distinct packets that only depend on the frequency, f (or wavelength) (the photoelectric effect)... E=hv, h is plancks constant.
so E = pc = hf and finally, p = hf / c
astropixie101 2 years ago 15
Usually I have great admiration for the sixtysymbols videos. But the explanation of Rayleigh scattering at 5:30 makes no sense.
The wavelengths from red down to blue are all much larger than the size of a molecule. In all cases the molecules 'experiences' an effectively uniform electromagnetic field, oscillating very rapidly. It is easy to show that this gives rise to the famous 1/lambda^4 spectrum of Rayleigh scattering.
materiasacra 7 months ago