SUPER-EFFICIENT ENGINE Formula Revealed

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Uploaded by on Nov 5, 2011

Formula : Ft = Fp x e
Ft = the active effort tending to turn the crank
Fp= Piston force during power stroke ( based from Automotive Encyclopedia by Toboldt & Johnson pg.98)
e = crank's efficiency in harnessing the piston force ( based from Internal Combustion Engines by Maleev pg. 443)

ACTIVE EFFORT TENDING TO TURN THE CRANK ( Ft ) SUMMARY ( Based from Force Vector Diagram shown on video). Comparison were based from same amount of power input. Note below the maximum Ft for conventional & invention engine.

Ft Conventional Engine( Top) : Ft Invention(Bottom)
@ TDC=0 Conventional : 0 invention
@10deg=435.13 lbs force : 906.53 invention
@20deg=1121.16 : 1590.3
@30deg=1506.66 : 2226.6 lb.f (maximum)
@40deg=1519.87 lbs force (maximum) : 1880.05
@50deg=1448.76 : 1626
@60deg=1242.74 : 1272
@70deg=1083.32 : 1060
@80deg=909.12 : 883.5
@90deg=777.5 : 777.5
@100deg=598.47 : 636
@110deg=484.63 : 565.5
@120deg=400.15 : 530
@130deg=317.29 : 495
@140deg=238.02 : 436.53
@150deg=165.78 : 339.2
@160deg=92.26 : 176.75
@170deg=41.66 : 124.02
@BDC=0 : 0

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Uploader Comments (died4hislove)

  • You can now watch the explanation on why my engine system is super-efficient by watching the following videos:

    1.) Principles That Makes My Engine SUPER-EFFICIENT ( Part 1)

    2.) Principles That Makes My Engine SUPER-EFFICIENT ( Part 2)

    3.) Principles That Makes My Engine SUPER-EFFICIENT ( Part 3)

    4.) Principles That Makes My Engine SUPER-EFFICIENT ( Part 4)

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  • Yup... I think this explanation is flawed... Force is not equal to power !! Force * speed = power. There is no energy lost by the crank force being smaller than the Piston force, because it is only a mechanical translation i.e. what we loose in force we gain in speed. Or better the other way round (constant crank speed) the energy from the compression in the Cylinder is just not translated at a constant rate to mecahnical energy, which doesn't mean that energy is lost.

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