Simple elliptical straightedge ORBOX compressor engine
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A template/stencil is easily printed (even Powerpoint).
orboxbe 1 year ago
Example, take t=12, s=5, we have rotor-pivot distance=13, and area 169-(3.14*5*6) = 75.
If you want a compression ratio of 10 and circular combustion chamber, the area should be 7.5 or a diameter of 1.5.
A rotor thickness of 2 would now give a minimum volume of 15, and a maximum volume of 150. Scale as you like (x 1cm?).
orboxbe 1 year ago
You can almost completely fill the minimum volume for high compression. The max volume is approx. (t*t+s*s) - (pi*t*s)/2 times the thickness of the rotor. The maximum volume can be easily calculated considering the ellipse has a surface of pi*t*s, with t and s half the max and min diameter.
The distance between rotor and pivot axis is sqrt(t*t+s*s), so the square as max expansion is 2(t*t+s*s). Substract the rotor surface, and divide by 2, to get the surface at only one side of the rotor.
orboxbe 1 year ago
a straightedge orbiting an ellipse describes a cirkel :
(just google for Apollonius Fermat cirkel )
so a rotating ellipse and a pivoting straightedge confine a variable volume
as far as I can find nobody ever used this feature. Why not?
orboxbe 1 year ago