College Algebra - Lecture 27 - Rational Functions
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Top Comments
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Wow great explanations! Very clear and straight forward! This will definitely help since my teacher is not exactly "teaching".... It's good to know that I can learn elsewhere to prep for my exam:S
All Comments (21)
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why do you shift to the right instead of the left when its (-2)? at 14:30 / nevermind ok so you actually say you 'started' at 2 and then subtract 2 and subtract 1 to get to 0,0.
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why do you shift to the right instead of the left when its (-2)? at 14:30
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how are you so good at sketching those graphs! Ugh!
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@blitzmitz Doug Hauf Lecture 27
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@bvlgary09 Doug Hauf Watched Lecture 27
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What's so special about an asymptote if the function can go through it?
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@umkc At 0:41:34 how did you know that the function was going to look like that specifically?
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wow, you're better than all the math teachers ive ever had
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Hey I go to a community school and my teacher is horrible. You're videos are the reason I'm passing with a high A. I'm impressed with how neat you lesson plan and note-giving is. Thanks the most.
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how would you know what values of x and y intercepts to further convince that your graph is right?
bvlgary09 2 years ago
I'm not sure what you are really asking, but, assuming you have been given a function of the form y = f(x), any x-intercept is gotten, by definition, by letting y = 0 [because y = 0 precisely when the point of the graph lies on the x-axis and hence has the form (x,0) ] and then solving for values of x that make this happen. Likewise, any y-intercept is gotten by letting x = 0, and then solving for values of y that make this happen. This is a general technique for any function.
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UMKC 2 years ago 3