How To: Solve Problems Involving Dilution

Loading...

Sign in or sign up now!
Alert icon
Upgrade to the latest Flash Player for improved playback performance. Upgrade now or more info.
10,942
Loading...
Alert icon
Sign in or sign up now!
Alert icon

Uploaded by on Sep 11, 2008

In this video I show you how to solve 2 problems involving dilution.

--PLEASE LEAVE COMMENTS--

Category:

Education

Tags:

License:

Standard YouTube License

  • likes, 2 dislikes

Link to this comment:

Share to:
see all

All Comments (17)

Sign In or Sign Up now to post a comment!
  • Thank you so much :)

  • Those problems are correct The 1st problem is correct but it should be rounded off and should be 667 mL from the final computation 666.66

    the 2nd problem is correct, volumes can be in mL or in L, depending on what it is needed. it is more practical to use the mL because the given V2 is in mL.

  • The second problem is actually incorrect. Volume can only be calculate in L, and in the example it shows it in mL; therefore, you have to divide150mL by 1000mL in a Liter, and the actual answer is 0.075 L... I didn't do the first problem, but my guess is that it is also wrong.

    Best of luck.

  • niceeeeeeee thank you,it's helps me alot ,yehey!!!!!xx

  • Nice and simple! Thank you :)

  • Great video. I wish I discovered this two semesters ago.

  • Basically my teacher pulled a problem like this out of his ass. He never taught us how to do it or anything. thanks for your help Hopefully ill get it on the final

  • Helped me extremely for my Chem Final, Thanks!

  • Thanks, I'm glad you decided to make this video, it was really helpful

  • The second problem has such round numbers you can eyeball it. Half the molarity means you've doubled the volume of solution, so V1 = 1/2 of V2.

Loading...
Alert icon
0 / 00Unsaved Playlist Return to active list
    1. Your queue is empty. Add videos to your queue using this button:
      or sign in to load a different list.
    Loading...Loading...Saving...
    • Clear all videos from this list
    • Learn more