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37) The Area Under a Curve: approx. the definite intergral

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Uploaded by on Nov 12, 2007

The Area Under a Curve
Produced by
Kent Murdick
Instructor of Mathematics
University of South Alabama

  • likes, 6 dislikes

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Uploader Comments (Lutemann)

  • I used the fundamental theorem of calculus.

  • why did you use n=4?? or is it just an arbitrairy choice

    thanx for sharing the knowledge

  • It's arbitrary. If you can do it with four then you can do it with three or ten or whatever. Four comes out pretty neat, though.

  • Nice video, though I'd like to point out that you didn't mention that this particular example is a right-hand Riemman sum, nor did you mention that there are three more types of Riemman sums, two of which give a more accurate area. I think that info would have made the video more helpful. Other than that good work.

  • You are correct and I show my students the more general approach, but this is the only one they are responisble for. The right sum is the one they will use in most applications.

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  • @denissjacenko the indefinite integral of x squared is x cubed over 3 ∫x^2 dx = (x^3)*(1/3) The integral is like the anti derivative. so if you take the derivative of (x^3)*(1/3) you get x^2 now using this integral, evaluate from 1 to 3

    this means that you plug in 3 for x into (x^3)*(1/3) and subtract 1 plugged into (x^3)*(1/3). so you have (3^3)*(1/3) - (1^3)*(1/3) = 27/3 - 1/3 = 26/3

  • how did you get 26/3?

  • Good video and you explain it very well, n=4 as partitions are good, n=5 is also well. Do you have more examples of the definite integreals that someone might use in a real life situations? thanks for your time.

  • 5 stars yea.. sorry no stars in the rating system anymore

    anyway thanks a lot

  • at the end you said twenty three thirds instead of twenty 26 lol.

    Great video though, 5 stars

  • Thanks

  • you have 4 rectangles between 1 and 3. the bases of these are 1 to x1, x1 to x2, x2 to x3 and x3 to 3 right? so x1 = 1 + delta x. delta x is .5 so x1 = 1.5 then x2 = 1.5 + .5 = 2 and so on

  • why did the roots of the squares increase? i.e x1= 1.5, x2=2, x3=2.5etc...?

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