so two quick questions, had you placed the fluorine on the equatorial down position (as opposed to the up axial) then would that be Trans -1-ethyl-4-flourocyclohexane ? also would it be right to place the ethyl on an axial down position and then the flouro would be on an equatorial down as well ? thanks
so two quick questions, had you placed the fluorine on the equatorial down position (as opposed to the up axial) then would that be Trans -1-ethyl-4-flourocyclohexane ? also would it be right to place the ethyl on an axial down position and then the flouro would be on an equatorial down as well ? thanks
caorr 1 week ago
thank you !!!!!!! :)
caorr 1 week ago
thanks man for clearing up my confusion
blahblahblahtape 4 weeks ago
nice job explaining!
DeesWorld007 2 months ago
Thanks for sharing, this helped clarity some confusion!
BRENNANSTECHBITE 4 months ago
I guess the first ring is more stable because the larger substituent (ethyl) is in the equatorial position.
weiyi1123 5 months ago
THANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOUTHANK YOU
heyyylyla 5 months ago
Ah nice, this was way easier to follow than my textbook. Thank you!
Nullmech 5 months ago
thank you. :)
AthrunZala32 5 months ago
thank you so much!! you have made ring flip and stability understandable!!! great explanation!
khaniiiiii 8 months ago