Solve Trigonometric Equations Part 1

This lesson shows how to solve trigonometric equations involving mostly exact values from the unit circle. This is the first part of a two part lesson. This lesson was created for the MFH4U Advanced Functions course in the province of Ontario, Canada.

Category:

Education

Tags:

• MFH4U
• Advanced
• Functions

[zacmiley12]

How would I solve 3sin2x-1 in the same way in your video?

[AlRichards314]

@zacmiley12 I assume you mean 3sin2x-1 = 0

bring the 1 over: 3sin2x = 1

divide both sides by 3: sin2x = 1/3

Solve for 2x: 2x = sin^-1(1/3)

Divide by 2: x = (1/2)sin^-1(1/3)

In degrees: x = (1/2)[19.47,160.53] 180 - 19.47 = 160.53 degrees

Therefore x = 9.735, 80.265

In radians x = 0.1699, 1.4009

[dillzchaitoo]

okay...to be honest! i really dont understand

[AlRichards314]

@dillzchaitoo What parts?

[bigteck1]

Thank you so much...my teacher has been teaching this for about 2 weeks and by watching only this video i finally understand everything my teacher tried to teach us...Thank you so much and keep it up. I'm looking forward to watching all your videos

[AlRichards314]

Thanks for the comment. It is good to hear when someone finds my videos clear and helps them understand some math.

[iMetalNeko]

i agree with muffincita5 :) thank you so much for the help! i get unit circles better now :D

[muffincita5]

What a great video! Thank you so much.

[firered84]

you are a math god...

[osvideosdojoao]

I understood all video, and I'm not an english native.I'm from Portugal. The video is very good, and the spoken english is easy.

[L3evyy]

can you please help me prove this

tan(x-3pi/2)=-cotx

thanks

[titanic1224]

OMG! Thank you i have been so confused on how to do this...